YT06-背包-1001—Bone Collector -(6.27日-烟台大学ACM预备队解题报告)
2015-07-15 17:13
459 查看
Bone Collector
Time Limit : 2000/1000ms (Java/Other) Memory Limit : 32768/32768K (Java/Other)Total Submission(s) : 58 Accepted Submission(s) : 25
Font: Times New Roman | Verdana | Georgia
Font Size: ← →
Problem Description
Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave …The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the
maximum of the total value the bone collector can get ?
Input
The first line contain a integer T , the number of cases.Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third
line contain N integers representing the volume of each bone.
Output
One integer per line representing the maximum of the total value (this number will be less than 231).Sample Input
1 5 10 1 2 3 4 5 5 4 3 2 1
Sample Output
14
Author
TeddySource
HDU 1st “Vegetable-Birds Cup” Programming Open Contest题意:用包按顺序收集骨头,给出包可收纳骨头的数量和各种骨头的数量及其价值,求可获得的最大价值。
思路:每种骨头按照包的剩余容量选择是否收集
状态:large[j]:表示收集了volume为j时的最大价值
状态转移:large[j]=max(large[j],large[j-volume[i]]+value[i])
#include<cstdio> #include<cstring> #include<iostream> using namespace std; int main() { int i,j; int t,n,v; int large[1006],volume[1006],value[1006]; scanf("%d",&t); while(t--) { scanf("%d%d",&n,&v); for(i=1;i<=n;i++) scanf("%d",&value[i]); for(i=1;i<=n;i++) scanf("%d",&volume[i]);memset(large,0,sizeof(large)); for(i=1;i<=n;i++) for(j=v;j>=volume[i];j--) large[j]=max(large[j],large[j-volume[i]]+value[i]); printf("%d\n",large[v]); } return 0; }
相关文章推荐
- [Elasticsearch] 部分匹配 (二) - 通配符及正则表达式查询
- linux系统编程:进程间通信-pipe
- 洛谷-牛数-野题
- Hadoop集群硬盘故障分析与自动化修复
- Hadoop集群硬盘故障分析与自动化修复
- linux下配置git版本控制工具
- 微信企业号开发:corpsecret到底在哪块呢?
- html 文字和图片左右居中效果
- iOS 使用Quartz 2D画虚线
- Android事件分发机制完全解析,带你从源码的角度彻底理解(上)
- [Elasticsearch] 部分匹配 (一) - 前缀查询
- java.nio.ByteBuffer中flip、rewind、clear方法的区别
- java-泛型返回值的方法类型
- iOS开发之身份证号码校验
- 敏捷开发之道
- 动态调用webservice
- java Runtime.exec() 执行问题
- jQuery插件开发的五种形态小结
- CM3 STM32F的低功耗
- SSH框架