日期计算

#include <stdio.h>
int main()
{
int k;
scanf("%d",&k);
int n,y,r,flag=0;
int a[2][13]={
{0,31,28,31,30,31,30,31,31,30,31,30,31},
{0,31,29,31,30,31,30,31,31,30,31,30,31}
};
while(k--)
{
int days=0;
scanf("%d %d %d",&n,&y,&r);
flag=(n%4==0 && n%100!=0 || n%400==0) ? 1:0;
for(int i=0;i<y;i++)
days+=a[flag][i];
days=days+r;
printf("%d\n",days);
}
return 0;
}