NYOJ 204 Coin Test
2015-07-07 17:26
211 查看
Coin Test
时间限制:3000 ms | 内存限制:65535 KB难度:1
描述
As is known to all,if you throw a coin up and let it droped on the desk there are usually three results. Yes,just believe what I say ~it can be the right side or the other side or standing on the desk, If you don't believe this,just try In the past there
were some famous mathematicians working on this .They repeat the throwing job once again. But jacmy is a lazy boy.He is busy with dating or playing games.He have no time to throw a single coin for 100000 times. Here comes his idea,He just go bank and exchange
thousands of dollars into coins and then throw then on the desk only once. The only job left for him is to count the number of coins with three conditions.
He will show you the coins on the desk to you one by one. Please tell him the possiblility of the coin on the right side as a fractional number if the possiblity between the result and 0.5 is no larger than 0.003. BE CAREFUL that even 1/2,50/100,33/66 are
equal only 1/2 is accepted ! if the difference between the result and 0.5 is larger than 0.003,Please tell him "Fail".Or if you see one coin standing on the desk,just say "Bingo" any way.
输入Three will be two line as input.
The first line is a number N(1<N<65536)
telling you the number of coins on the desk.
The second line is the result with N litters.The letter are "U","D",or "S","U" means the coin is on the right side. "D" means the coin is on the other side ."S" means standing on the desk.输出If test successeded,just output the possibility of the coin on the right side.If the test failed please output "Fail",If there is one or more"S",please output "Bingo"样例输入
6 UUUDDD
样例输出
1/2
相关文章推荐
- 数据库内存使用
- 错误: 编码GBK的不可映射字符
- 一个iOS 框架介绍:MKNetworkKit
- 设置python 命令行交互程序自动补齐
- hdu4288 Coder(段树+分离)
- 【LeetCode】217. Contains Duplicate (2 solutions)
- Java 8十个lambda表达式案例
- 将一个正整数分解质因数的两种方式
- Mybatis学习笔记
- UVA 796 - Critical Links (求桥,模板题)
- Android中ViewPager与HorizontalListView的滑动冲突处理
- iOS-ui-colorPicker
- HQL
- js拖动层原形版
- 利用ant脚本 自动构建svn增量/全量 系统程序升级包
- Sharepoint2013 获取用户邮箱信息
- easyui-validatebox 验证
- Machine Learning课程 by Andrew Ng
- UISlider/滑块
- jni dev