java List 排序 Collections.sort() 对 List 排序
2015-07-07 14:21
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//一个POJO例子
class User {
String name;
String age;
public User(String name,String age){
this.name=name;
this.age=age;
}
public String getAge() {
return age;
}
public void setAge(String age) {
this.age = age;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
}
//具体的比较类,实现Comparator接口
import java.util.Comparator;
import java.util.List;
import java.util.ArrayList;
import java.util.Collections;
public class ComparatorUser implements Comparator{
public int compare(Object arg0, Object arg1) {
User user0=(User)arg0;
User user1=(User)arg1;
//首先比较年龄,如果年龄相同,则比较名字
int flag=user0.getAge().compareTo(user1.getAge());
if(flag==0){
return user0.getName().compareTo(user1.getName());
}else{
return flag;
}
}
}
//测试类
public class SortTest {
public static void main(String[] args){
List userlist=new ArrayList();
userlist.add(new User("dd","4"));
userlist.add(new User("aa","1"));
userlist.add(new User("ee","5"));
userlist.add(new User("bb","2"));
userlist.add(new User("ff","5"));
userlist.add(new User("cc","3"));
userlist.add(new User("gg","6"));
ComparatorUser comparator=new ComparatorUser();
Collections.sort(userlist, comparator);
for (int i=0;i<userlist.size();i++){
User user_temp=(User)userlist.get(i);
System.out.println(user_temp.getAge()+","+user_temp.getName());
}
}
}
//首先年龄排序,如果年龄相同,则按名字排序
结果:
1, aa
2, bb
3, cc
4, dd
5, ee //注意:同样是5岁的人,则比较名字(ee,ff),然后排序
5, ff
6, gg
class User {
String name;
String age;
public User(String name,String age){
this.name=name;
this.age=age;
}
public String getAge() {
return age;
}
public void setAge(String age) {
this.age = age;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
}
//具体的比较类,实现Comparator接口
import java.util.Comparator;
import java.util.List;
import java.util.ArrayList;
import java.util.Collections;
public class ComparatorUser implements Comparator{
public int compare(Object arg0, Object arg1) {
User user0=(User)arg0;
User user1=(User)arg1;
//首先比较年龄,如果年龄相同,则比较名字
int flag=user0.getAge().compareTo(user1.getAge());
if(flag==0){
return user0.getName().compareTo(user1.getName());
}else{
return flag;
}
}
}
//测试类
public class SortTest {
public static void main(String[] args){
List userlist=new ArrayList();
userlist.add(new User("dd","4"));
userlist.add(new User("aa","1"));
userlist.add(new User("ee","5"));
userlist.add(new User("bb","2"));
userlist.add(new User("ff","5"));
userlist.add(new User("cc","3"));
userlist.add(new User("gg","6"));
ComparatorUser comparator=new ComparatorUser();
Collections.sort(userlist, comparator);
for (int i=0;i<userlist.size();i++){
User user_temp=(User)userlist.get(i);
System.out.println(user_temp.getAge()+","+user_temp.getName());
}
}
}
//首先年龄排序,如果年龄相同,则按名字排序
结果:
1, aa
2, bb
3, cc
4, dd
5, ee //注意:同样是5岁的人,则比较名字(ee,ff),然后排序
5, ff
6, gg
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