Construct Binary Tree from Inorder and Postorder Traversal
2015-07-07 14:14
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/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ public class Solution { public TreeNode buildTree(int[] inorder, int[] postorder) { if (inorder.length != postorder.length) { return null; } return myBuildTree(inorder, 0, inorder.length - 1, postorder, 0, postorder.length - 1); } private TreeNode myBuildTree(int[] inorder, int inBeg, int inEnd, int[] postorder, int postBeg, int postEnd) { if (inBeg > inEnd) { return null; } TreeNode root = new TreeNode(postorder[postEnd]); int location = findLocation(inorder, inBeg, inEnd, postorder[postEnd]); root.left = myBuildTree(inorder, inBeg, location - 1, postorder, postBeg, postBeg + location - inBeg - 1); root.right = myBuildTree(inorder, location + 1, inEnd, postorder, postEnd + location - inEnd, postEnd - 1); return root; } private int findLocation(int[] inorder, int begin, int end, int value) { for (int i = begin; i <= end; i++) { if (inorder[i] == value) { return i; } } return -1; } }
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