您的位置:首页 > 其它

【NOI集训】【XJ】状压dp

2015-07-05 21:12 295 查看
首先贪心得不会有多于1种不选满(除了强制选的),再dp一下即可。

#include <iostream>
#include <cstdio>
#include <algorithm>
#include <cstring>
#include <cmath>
#include <string>
#define Rep(i, x, y) for (int i = x; i <= y; i ++)
#define RepE(i, x) for (int i = pos[x]; i; i = g[i].nex)
#define Dwn(i, x, y) for (int i = x; i >= y; i --)
using namespace std;
typedef long long LL;
const int N = 100005, M = N * 2, K = 103, D = 70;
struct arr { int p[K]; } a[M];
int n, m, d, n0, ans, s, f[M][D], h[M][D], p, r[10];
bool cmp(arr x, arr y) { return x.p[d] > y.p[d]; }
int main()
{
//freopen("1.in", "r", stdin);
//freopen("1.out", "w", stdout);
scanf ("%d%d%d%d", &m, &n, &d, &s), n0 = n;
Rep(i, 1, m) {
Rep(j, 1, d) scanf ("%d", &a[i].p[j]);
}
sort(a+1, a+m+1, cmp);
Rep(i, 1, s) scanf ("%d", &r[i]);
Rep(i, 1, s) {
Rep(j, i+1, s) if (r[i] == r[j]) {
Rep(k, i, s-1) r[k] = r[k+1]; s --; i --; break ;
}
}
Rep(i, 1, s) n0 -= r[i];
if (n0 % d) r[++ s] = n0 % d; n0 /= d;
p = (1 << s) - 1;
memset(f, 63, sizeof(f));
memset(h, 0, sizeof(h));
f[0][0] = 0;
Rep(j, 1, m) {
Rep(k, 0, p) {
Rep(x, 1, s) {
if (!(k & (1 << x-1))) {
f[j][k + (1 << x-1)] = min(f[j][k + (1 << x-1)], f[j-1][k] - a[j].p[r[x]] + a[j].p[d]);
}
}
f[j][k] = min(f[j][k], f[j-1][k]);
}
}
Dwn(j, m, 1) {
Rep(k, 0, p) {
Rep(x, 1, s) if (!(k & (1 << x-1))) {
h[j][k + (1 << x-1)] = max(h[j][k + (1 << x-1)], h[j+1][k] + a[j].p[ r[x] ]);
}
h[j][k] = max(h[j][k], h[j+1][k]);
}
}
Rep(i, n0, n0+s) {
int ret = -(1 << 30);
Rep(k, 0, p) {
int t = 0;
Rep(x, 0, s-1) if (k & (1 << x)) t ++;
if (t == i - n0) ret = max(ret, h[i+1][p-k] - f[i][k]);
}
Rep(j, n0 + 1, i) ret += a[j].p[d];
ans = max(ans, ret);
}
Rep(i, 1, n0) ans += a[i].p[d];
printf("%d\n", ans);
return 0;
}
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: