A + B Again 2057 有符号的64进位的运算
2015-07-05 15:57
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[align=left]Problem Description[/align]
There must be many A + B problems in our HDOJ , now a new one is coming.
Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too.
Easy ? AC it !
[align=left]Input[/align]
The input contains several test cases, please process to the end of the file.
Each case consists of two hexadecimal integers A and B in a line seperated by a blank.
The length of A and B is less than 15.
[align=left]Output[/align]
For each test case,print the sum of A and B in hexadecimal in one line.
[align=left]Sample Input[/align]
+A -A
+1A 12
1A -9
-1A -12
1A -AA
[align=left]Sample Output[/align]
0
2C
11
-2C
-90
[align=left]Author[/align]
linle
[align=left]Source[/align]
校庆杯Warm Up
[align=left]Recommend[/align]
linle | We have carefully selected several similar problems for you: 2060 2058 2056 2059 2061
There must be many A + B problems in our HDOJ , now a new one is coming.
Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too.
Easy ? AC it !
[align=left]Input[/align]
The input contains several test cases, please process to the end of the file.
Each case consists of two hexadecimal integers A and B in a line seperated by a blank.
The length of A and B is less than 15.
[align=left]Output[/align]
For each test case,print the sum of A and B in hexadecimal in one line.
[align=left]Sample Input[/align]
+A -A
+1A 12
1A -9
-1A -12
1A -AA
[align=left]Sample Output[/align]
0
2C
11
-2C
-90
[align=left]Author[/align]
linle
[align=left]Source[/align]
校庆杯Warm Up
[align=left]Recommend[/align]
linle | We have carefully selected several similar problems for you: 2060 2058 2056 2059 2061
#include<stdio.h> int main() { long long int x,y,z; while(~scanf("%llx%llx",&x,&y)) { (x+y>=0)?printf("%llX\n",x+y):printf("-%llX\n",-(x+y)); } return 0; }
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