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Shortest Palindrome leetcode-java

2015-07-01 13:35 633 查看


先制作原字符串的对称镜像字符串,如s = “abcd”, 镜像a = “abcddcba”+” “。

然后对新字符串a,按KMP算法求next的方法,求next

KMP算法请参考:

http://blog.csdn.net/tukangzheng/article/details/38438481

public class Solution {
public String shortestPalindrome(String s) {
if(s.length() == 0||s.length() == 1)
return s;
String mirror = s + new StringBuilder(s).reverse().toString()+" ";
int[] next = new int[mirror.length()];
int i=0;
int j=-1;
next[0]=-1;
while(i<mirror.length()-1){
if(j==-1||mirror.charAt(i)==mirror.charAt(j)){
i++;
j++;
next[i]=j;
}else j=next[j];
}
int count = s.length() - next[mirror.length() -1];
if(count<0)count =0;
String result = new StringBuilder(s.substring(s.length()-count, s.length())).reverse().toString() + s;
return result;
}
}
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标签:  leetcode java