纳什均衡

[code]#include <iostream>
#include <cstdio>
using namespace std;
long long  gcd(long long m, long long  n)
{
    if(n == 0)
        return m;
    return gcd(n,m%n);
}
int main()
{
   long long T, A, B;
   cin>>T;
   while(T--)
   {
       cin>>A>>B;
       long long  sum=2*(A+B);
       long long  ans=(A+B)/2+B;
       long long  as=gcd(ans,sum);
       cout<<ans/as<<"/"<<sum/as<<endl;
   }
}