您的位置:首页 > 其它

LeetCode203——Remove Linked List Elements

2015-05-24 22:51 267 查看
Remove all elements from a linked list of integers that have value val.

Example Given: 1 --> 2 --> 6 --> 3 --> 4 --> 5 --> 6, val = 6 Return: 1 --> 2 --> 3 --> 4 --> 5

Credits: Special thanks to @mithmatt for adding this problem and creating all test cases.

实现:
[code]ListNode* removeElements(ListNode* head, int val) {
    ListNode* currNode = head;
    while (true) {
        if (head == NULL) return NULL;
        if (currNode->val != val) break;
        currNode = currNode->next;
        head = currNode;
    }
    while (currNode->next) {
        if (currNode->next->val == val) {
            currNode->next = currNode->next->next;
        } else {
            currNode = currNode->next;
        }
    }
    return head;
}
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: