PAT 1011. World Cup Betting (20)
2015-05-19 18:50
363 查看
With the 2010 FIFA World Cup running, football fans the world over were becoming increasingly excited as the best players from the best teams doing battles for the World Cup trophy in South Africa. Similarly, football betting fans were putting their money where
their mouths were, by laying all manner of World Cup bets.
Chinese Football Lottery provided a "Triple Winning" game. The rule of winning was simple: first select any three of the games. Then for each selected game, bet on one of the three possible results -- namely W for win, T for tie, and L for lose. There was an
odd assigned to each result. The winner's odd would be the product of the three odds times 65%.
For example, 3 games' odds are given as the following:
To obtain the maximum profit, one must buy W for the 3rd game, T for the 2nd game, and T for the 1st game. If each bet takes 2 yuans, then the maximum profit would be (4.1*3.0*2.5*65%-1)*2 = 37.98 yuans (accurate up to 2 decimal places).
Input
Each input file contains one test case. Each case contains the betting information of 3 games. Each game occupies a line with three distinct odds corresponding to W, T and L.
Output
For each test case, print in one line the best bet of each game, and the maximum profit accurate up to 2 decimal places. The characters and the number must be separated by one space.
Sample Input
Sample Output
此题较为简单, 以下是代码
:
their mouths were, by laying all manner of World Cup bets.
Chinese Football Lottery provided a "Triple Winning" game. The rule of winning was simple: first select any three of the games. Then for each selected game, bet on one of the three possible results -- namely W for win, T for tie, and L for lose. There was an
odd assigned to each result. The winner's odd would be the product of the three odds times 65%.
For example, 3 games' odds are given as the following:
W T L 1.1 2.5 1.7 1.2 3.0 1.6 4.1 1.2 1.1
To obtain the maximum profit, one must buy W for the 3rd game, T for the 2nd game, and T for the 1st game. If each bet takes 2 yuans, then the maximum profit would be (4.1*3.0*2.5*65%-1)*2 = 37.98 yuans (accurate up to 2 decimal places).
Input
Each input file contains one test case. Each case contains the betting information of 3 games. Each game occupies a line with three distinct odds corresponding to W, T and L.
Output
For each test case, print in one line the best bet of each game, and the maximum profit accurate up to 2 decimal places. The characters and the number must be separated by one space.
Sample Input
1.1 2.5 1.7 1.2 3.0 1.6 4.1 1.2 1.1
Sample Output
T T W 37.98
此题较为简单, 以下是代码
#include <iostream> #include <iomanip> using namespace std; int main(void) { float W[3],T[3],L[3],max[3],pro; char result[3]; int i; for(i=0;i<3;i++) { cin>>W[i]>>T[i]>>L[i]; max[i]=W[i]; result[i]='W'; if(max[i]<T[i]) { max[i]=T[i]; result[i]='T'; } if(max[i]<L[i]) { max[i]=L[i]; result[i]='L'; } } pro=1; for(i=0;i<3;i++) { cout<<result[i]<<" "; pro*=max[i]; } pro=(pro*0.65-1)*2; cout.setf(ios::fixed); cout.precision(2); cout<<pro; return 0; }
:
相关文章推荐
- PAT甲级.1011. World Cup Betting (20)
- pat 1011. World Cup Betting (20)
- 【PAT Advanced Level】1011. World Cup Betting (20)
- pat甲级1011. World Cup Betting (20)
- PAT甲题题解-1011. World Cup Betting (20)-误导人的水题。。。
- PAT甲级真题及训练集(7)--1011. World Cup Betting (20)
- PAT甲级 1011. World Cup Betting (20)
- PAT 1011World Cup Betting (20)
- PAT 甲级 1011. World Cup Betting (20)
- 浙江大学PAT上机题解析之1011. World Cup Betting (20)
- 1011. World Cup Betting (20) PAT 甲级
- PAT (Advanced Level) Practise 1011 World Cup Betting (20)
- PAT (Advanced Level)1011. World Cup Betting (20)
- PAT甲 1011. World Cup Betting (20)
- 【PAT Advanced Level】1011. World Cup Betting (20)
- PAT-PAT (Advanced Level) Practise 1011. World Cup Betting (20) (套公式) 【一星级】
- PAT 1011. World Cup Betting (20)
- PAT (Advanced Level) Practise 1011. World Cup Betting (20)
- 【c++】PAT (Advanced Level)1011. World Cup Betting (20)
- PAT (Advanced Level) 1011. World Cup Betting (20) 求最大期望值,简单题