LeetCode 100: Same Tree
2015-05-14 12:46
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Given two binary trees, write a function to check if they are equal or not.
Two binary trees are considered equal if they are structurally identical and the nodes have the same value.
分析:
题目要求判断两棵树是否相同,首先判断根节点是否相同,如果根节点相同,分别判断左、右子树是否相同。
代码如下:
Two binary trees are considered equal if they are structurally identical and the nodes have the same value.
分析:
题目要求判断两棵树是否相同,首先判断根节点是否相同,如果根节点相同,分别判断左、右子树是否相同。
代码如下:
/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: bool isSameTree(TreeNode* p, TreeNode* q) { if (p==NULL && q==NULL) { return true; } if ((p==NULL && q!=NULL) || (p!=NULL &&q==NULL)) { return false; } if (p->val != q->val) { return false; } return isSameTree(p->left, q->left) && isSameTree(p->right ,q->right); } };
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