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C++ Primer 课后习题9.39 统计单词个数并记录最大单词和最短单词

2015-05-12 14:33 465 查看
习题9.39: 已知有如下string对象:

string line1 = "We were her pride of 10 she named us:";
string line2 = "Benjamin, Phoenix, the Prodigal";
string line3 = "and perspicacious perspicacious pacific Suzanne";
string sentence = line1 + ' ' + line2 + ' ' + line3;


编写程序计算sentence中有多少个单词,并指出其中最长和最短的单词。如果有多个最短或者最长单词,则将他们全部输出。

代码:

 #include <iostream>
#include <vector>
#include <list>
#include <string>
#include <deque>
#include <algorithm>
#include <sstream>
using namespace std;

int main(int argc, char **argv)
{
string num("0123456789");
string alpha("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ");
string alphanum = num + alpha;
string line1 = "We were her pride of 10 she named us:"; string line2 = "Benjamin, Phoenix, the Prodigal"; string line3 = "and perspicacious perspicacious pacific Suzanne"; string sentence = line1 + ' ' + line2 + ' ' + line3;
stringstream ss;
ss.str(sentence);
string str;
string strMax;
string strMin;
vector<string> vStrMax;
vector<string> vStrMin;
int sum = 0;
while (ss>>str)
{
sum++;
string::size_type pos = 0;
//删除非字母字符
while ((pos = str.find_first_not_of(alphanum,pos)) != string::npos)
{
str.erase(pos);
}
//比较获取最大单词
if (str.size() > strMax.size())
{
strMax = str;
vStrMax.clear();
vStrMax.push_back(str);
}else if (str.size() == strMax.size())
{
vStrMax.push_back(str);
}
//比较获取最小单词,注意strMin第一次大小为0
if (str.size() < strMin.size() || strMin.size() == 0)
{
strMin = str;
vStrMin.clear();
vStrMin.push_back(str);
}else if (str.size() == strMin.size())
{
vStrMin.push_back(str);
}
}
return 0;
}


总结:(1)使用字符串流处理字符串,获取单个单词;

   (2)使用string的find_first_not_of()方法除去“,:”非单词字符。
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