[leetcode][string] Implement strStr()
2015-05-11 19:21
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题目:
Implement strStr().
Returns the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack.
Update (2014-11-02):
The signature of the function had been updated to return the index instead of the pointer. If you still see your function signature returns a
reset your code definition.
遇到了两个很诡异的问题:
1.在leetcode中,用new动态分配数组会出现Runtime Error,而用变量(!!!)表示数组长度直接分配空间。不懂不懂。。。。。。
2.在vs2013中,可以new数组,但是delete []next时程序就跑飞了,在调用getNext之前delete就没问题,难道vs在编译时做了什么优化?不懂不懂。。。。。。
谁能告诉我这是什么鬼。。。。。。
Implement strStr().
Returns the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack.
Update (2014-11-02):
The signature of the function had been updated to return the index instead of the pointer. If you still see your function signature returns a
char *or
String, please click the reload button to
reset your code definition.
class Solution { public://KMP int strStr(string haystack, string needle) { if(needle.empty()) return 0; if(haystack.empty()) return -1; // int *next = new int[needle.size()]; int next[needle.size()]; getNext(needle, next); int i = 0, j = 0; int lenHaystack = haystack.size(); int lenNeedle = needle.size(); while(i < lenHaystack && j < lenNeedle){ if(j == -1 || haystack[i] == needle[j]){ ++j; ++i; } else j = next[j];//不匹配额时候不不移动i指针 } // delete []next; return j == needle.size() ? i - j : -1; } private: void getNext(string needle, int *next){ next[0] = -1; int i = 0, j = -1; while(i < needle.size()){ if(j == -1 || needle[i] == needle[j]){ ++i; ++j; next[i] = j; } else{//不匹配额时候不不移动i指针 j = next[j]; } } } };
遇到了两个很诡异的问题:
1.在leetcode中,用new动态分配数组会出现Runtime Error,而用变量(!!!)表示数组长度直接分配空间。不懂不懂。。。。。。
2.在vs2013中,可以new数组,但是delete []next时程序就跑飞了,在调用getNext之前delete就没问题,难道vs在编译时做了什么优化?不懂不懂。。。。。。
谁能告诉我这是什么鬼。。。。。。
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