leetcode--3Sum Closest
2015-05-05 18:41
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Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution.
public class Solution {
public int threeSumClosest(int[] nums, int target) {
int result = nums[0]+nums[1]+nums[2];
Arrays.sort(nums);
for(int i=0;i<nums.length;i++){
int low = i+1;
int high = nums.length-1;
while(low<high){
if(Math.abs(nums[low]+nums[high]+nums[i]-target)<Math.abs(result-target)){
result = nums[low]+nums[high]+nums[i];
}
if(nums[low]+nums[high]==target-nums[i]){
return target;
}else if(nums[low]+nums[high]<target-nums[i]){
low++;
}else{
high--;
}
}
}
return result;
}
}
For example, given array S = {-1 2 1 -4}, and target = 1. The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).
public class Solution {
public int threeSumClosest(int[] nums, int target) {
int result = nums[0]+nums[1]+nums[2];
Arrays.sort(nums);
for(int i=0;i<nums.length;i++){
int low = i+1;
int high = nums.length-1;
while(low<high){
if(Math.abs(nums[low]+nums[high]+nums[i]-target)<Math.abs(result-target)){
result = nums[low]+nums[high]+nums[i];
}
if(nums[low]+nums[high]==target-nums[i]){
return target;
}else if(nums[low]+nums[high]<target-nums[i]){
low++;
}else{
high--;
}
}
}
return result;
}
}
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