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FZU 2192 位置信息挖掘 (并查集或暴力)

2015-05-03 16:51 267 查看
思路:将城市一样,并且相互未知的联一条边.

然后对每一个已知的城市进行遍历,将和他相同的点,并且是未知的,变成已知.

跑多次.直到不再增加新点为止.

#define _CRT_SECURE_NO_WARNINGS
#include<cstring>
#include<cstdio>
#include<algorithm>
#include<iostream>
#include<vector>
using namespace std;
#define MAX 210000
int head[MAX<<1];
int r[MAX];
int s[MAX];
bool vis[MAX<<1];
int cnt;
struct edge
{
int v;
int next;
}edg[MAX<<2];
void init()
{
cnt = 0;
memset(head, -1, sizeof head);
memset(r, 0, sizeof r);
memset(s, 0, sizeof s);
}

void addedge(int u, int v)
{
edg[cnt].v = v;
edg[cnt].next = head[u];
head[u] = cnt++;
}

int main()
{
int n, m, q;
while (~scanf("%d%d%d", &n, &m, &q))
{
int id, tg;
init();
for (int i = 0; i < n; i++)
{
scanf("%d%d", &id, &tg);
s[id] = tg;
}
int aa, aaa, aaaa;
for (int i = 1; i <= m; i++)
{
scanf("%d%d%d", &aa, &aaa, &aaaa);
if (aaaa)
r[aa] = aaaa;
if (s[aaa])
{
r[aa] = s[aaa];
}
else
if (r[aa])
s[aaa] = r[aa];
else
{
addedge(aaa, aa + n);
addedge(aa + n, aaa);
}
}
int cnt = 0;
int pre = -1;
memset(vis, 0, sizeof vis);
while (cnt !=pre)
{
pre = cnt;
for (int i = 1; i <= n;i++)
if (s[i])
{
if (!vis[i])
{
vis[i] = 1;
cnt++;
}
for (int j = head[i]; j != -1;j = edg[j].next)
{
r[edg[j].v-n] = s[i];
if (!vis[edg[j].v])
{
vis[edg[j].v] = 1;
cnt++;
}
}
}
for (int i = 1; i <= m;i++)
if (r[i])
{
if (!vis[n+i])
{
vis[n+i] = 1;
cnt++;
}
for (int j = head[n+i]; j != -1; j = edg[j].next)
{
s[edg[j].v] = r[i];
if (!vis[edg[j].v])
{
vis[edg[j].v] = 1;
cnt++;
}
}
}
}
while (q--)
{
int u, v;
scanf("%d%d", &u, &v);
if (u == 0)
printf("%d\n", s[v]);
else
printf("%d\n", r[v]);
}
}
}
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