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第八周项目一-实现复数类中的运算符重载(2)

2015-04-29 09:02 274 查看
(2)请用类的友元函数,而不是成员函数,再次完成上面提及的运算符的重载;

/* Copyright (c) 2014, 烟台大学计算机学院
* All rights reserved.
* 文件名称:test.cpp
* 作者:陈丹妮
* 完成日期:2015年 4 月 29 日
* 版 本 号:v1.0
*/

#include <iostream>
using namespace std;
class Complex
{
public:
Complex(double r=0,double i=0):real(r),imag(i){}
friend Complex operator+(Complex &c1,Complex &c2);
friend Complex operator-(Complex &c1,Complex &c2);
friend Complex operator*(Complex &c1,Complex &c2);
friend Complex operator/(Complex &c1,Complex &c2);
void display();
private:
double real;
double imag;
};
//下面定义成员函数
//复数相加: (a+bi)+(c+di)=(a+c)+(b+d)i.
Complex operator+(Complex &c1,Complex &c2)
{
Complex c;
c.real=c1.real+c2.real;
c.imag=c1.imag+c2.imag;
return c;
}

//复数相减:(a+bi)-(c+di)=(a-c)+(b-d)i.
Complex operator-(Complex &c1,Complex &c2)
{
Complex c;
c.real=c1.real-c2.real;
c.imag=c1.imag-c2.imag;
return c;
}

//复数相乘:(a+bi)(c+di)=(ac-bd)+(bc+ad)i
Complex operator*(Complex &c1,Complex &c2)
{
Complex c;
c.real=c1.real*c2.real-c1.imag*c2.imag;
c.imag=c1.imag*c2.real+c1.real*c2.imag;
return c;
}

//复数相除:(a+bi)/(c+di)=(ac+bd)/(c^2+d^2) +(bc-ad)/(c^2+d^2)i
Complex operator/(Complex &c1,Complex &c2)
{
Complex c;
c.real=(c1.real*c2.real+c1.imag*c2.imag)/(c2.real*c2.real+c2.imag*c2.imag);
c.imag=(c1.imag*c2.real-c1.real*c2.imag)/(c2.real*c2.real+c2.imag*c2.imag);
return c;
}
void Complex::display()
{
cout<<"("<<real<<","<<imag<<"i)"<<endl;
}
//下面定义用于测试的main()函数
int main()
{
Complex c1(3,4),c2(5,-10),c3;
cout<<"c1=";
c1.display();
cout<<"c2=";
c2.display();
c3=c1+c2;
cout<<"c1+c2=";
c3.display();
c3=c1-c2;
cout<<"c1-c2=";
c3.display();
c3=c1*c2;
cout<<"c1*c2=";
c3.display();
c3=c1/c2;
cout<<"c1/c2=";
c3.display();
return 0;
}
<img src="http://img.blog.csdn.net/20150429090332151?watermark/2/text/aHR0cDovL2Jsb2cuY3Nkbi5uZXQvbnVmYW5nZG9uZ2Rl/font/5a6L5L2T/fontsize/400/fill/I0JBQkFCMA==/dissolve/70/gravity/Center" alt="" />
心得体会:注意在类的成员函数和在类的友元函数是有区别的,形参的形式不同。继续加油!
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