UVA424 Integer Inquiry

题目链接：http://acm.hust.edu.cn/vjudge/problem/viewProblem.action?id=19484

题意：给大数，问他们的和

思路：主要是练一下高精度。发现一个函数调用如果参数是数组，直接就会传地址而不需要&

源码：

#include <cstdio>

#include <cstring>

#include <cmath>

#include <algorithm>

#include <iostream>

using namespace std;

#define gmax(a,b) a>b?a:b

int const MAXN = 100+10;

char ans[MAXN];

struct D

{

char data[MAXN];

int len;

}d[MAXN];

void change(char ss[],int len)

{

int i,j;

for(i=0; i<len/2; i++){

char temp = ss[i];

ss[i] = ss[len-1-i];

ss[len-1-i] = temp;

}

}

int main()

{

int tot = 0,maxl = 0;;

while(scanf("%s",d[tot].data)!=EOF && d[tot].data[0] != '0'){

d[tot].len = strlen(d[tot].data);

maxl = gmax(d[tot].len,maxl);

change(d[tot].data,d[tot].len);

tot++;

}

int carry = 0;

int i,j,tt;

for(j=0; j<maxl; j++){

tt = 0;

for(i=0; i<tot; i++){

if(j>d[i].len-1)

continue;

tt += d[i].data[j] - '0';

}

tt += carry;

ans[j] = '0' + tt%10;

carry = tt/10;

}

while(carry){

ans[j++] = '0' + carry%10;

carry /= 10;

}

change(ans,j);

printf("%s\n",ans);

return 0;

}