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android背景设置报错 <item> tag requires a 'drawable' attribute or child tag defining a drawable<转>

2015-04-15 10:54 477 查看
android背景设置报错 tag requires a ‘drawable’ attribute or child tag defining a drawable<转>

今天本来只是想实现一个简单的按下ImageButton背景变颜色的功能,结果碰到 tag requires a ‘drawable’ attribute or child tag defining a drawable的错误。这句话的意思很简单,就是说item标签下需要drawable属性。在逛了无数国内论坛无果后,我尝试进了一个英文网站,结果如醍醐灌顶,深深的感觉到国内和国外的差距。

The problem here is that you cannot define the background color using a color selector, you need a drawable selector. So, the necessary changes would look like this:

你不能将颜色选择器用在background上,应该使用drawable selector,所以你应该这样修改(假设文件名为selector.xml):
<?xml version="1.0" encoding="utf-8"?>

<selector xmlns:android="http://schemas.android.com/apk/res/android">

<item

android:state_pressed="true"

android:drawable="@drawable/selected_state" />

</selector>awable/selected_state"/>

</selector>


You would also need to move that resource to the drawable directory where it would make more sense since it’s not a color selector per se.

Then you would have to create the res/drawable/selected_state.xml file like this:

同时你也要将selected_state.xml放在drawable目录下而不是color目录,然后这样定义res/drawable/selected_state.xml:

<?xml version="1.0" encoding="UTF-8"?>
<shape xmlns:android="http://schemas.android.com/apk/res/android"
android:shape="rectangle">
<solid android:color="@color/semitransparent_white" />
</shape>


and finally, you would use it like this:

最后在imageView中我们这样定义background:

android:background=”@drawable/selector”

其实这种方法将selector和颜色的定义分开了 我们可以将selector和shape的定义放在一起:

<selector xmlns:android="http://schemas.android.com/apk/res/android">
<item android:state_pressed="true">
<shape>
<solid android:color="#F1F1F1"/>
</shape>
</item>
<item android:state_selected="true">
<shape>
<solid android:color="#F1F1F1"/>
</shape>
</item>
</selector>
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