leetcode Merge Two Sorted Lists
2015-04-15 00:44
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代码:
#include<iostream> using namespace std; struct ListNode { int val; ListNode *next; ListNode(int x) : val(x), next(NULL) {} }; ListNode *mergeTwoLists(ListNode *l1, ListNode *l2) { if (l1 == NULL) return l2; if (l2 == NULL) return l1; ListNode *p = l1, *q = l2; ListNode *head; if (l1->val < l2->val) { head = l1; p = p->next; } else { head = l2; q = q->next; } ListNode *m = head; while (p != NULL&&q != NULL) { if (p->val < q->val) { m->next = p; p = p->next; m = m->next; } else { m->next = q; q = q->next; m = m->next; } } if (p == NULL) { m->next = q; } else { m -> next = p; } return head; } int main() { ListNode *a1 = (ListNode *)malloc(sizeof(ListNode)); ListNode *a2 = (ListNode *)malloc(sizeof(ListNode)); ListNode *a3 = (ListNode *)malloc(sizeof(ListNode)); ListNode *a4 = (ListNode *)malloc(sizeof(ListNode)); ListNode *a5 = (ListNode *)malloc(sizeof(ListNode)); a1->val = 2; a2->val = 3; a3->val = 6; a4->val = 9; a1->next = NULL; a2->next = a3; a3->next = a4; a4->next = NULL; ListNode *b1 = (ListNode *)malloc(sizeof(ListNode)); ListNode *b2 = (ListNode *)malloc(sizeof(ListNode)); ListNode *b3 = (ListNode *)malloc(sizeof(ListNode)); ListNode *b4 = (ListNode *)malloc(sizeof(ListNode)); ListNode *b5 = NULL; b1->val = 1; b2->val = 62; b3->val = 68; b4->val = 90; b1->next = NULL; b2->next = b3; b3->next = b4; b4->next = NULL; ListNode *m = mergeTwoLists(a1, b1); for (; m != NULL; m = m->next) cout << m->val << endl; }
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