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gridview展开嵌套显示

2015-04-13 15:20 288 查看
最近实在是太忙了,好几个月没有更新博客了,近来项目需要用到GRIDVIEW嵌套的,在这里跟大家分享一下,大家如有更好的解决方案,请不吝贴出。在ASP.NET中,GridView嵌套可以显示当前选定的父记录同时显示其子记录。例如,你可以创建按条件查找出相应项目的管理项目列表,同时可展开项目查看目前该项目进展到哪一阶段了。(如下图)

function HierarGrid_toggleRow(sender, grd) {
if (sender == null)
return;
var state = 1;
//if the hidden row has not already been generated, clone the panel into a new row
var existingRow = window.document.getElementById(sender.id + "showRow");
if (existingRow == null) {
//getting a reference to the table
var table = GetParentElementByTagName(sender, "TABLE");
var index = GetParentElementByTagName(sender, "TR").sectionRowIndex + 1;
//concatenate name of hidden panel => replace "Icon" from sender.id with "Panel"\n
if (grd == "grdProjectDetail1") {
rowDivName = HierarGrid_ReplaceStr(sender.id, "SHOW", grd);
}
else {
rowDivName = HierarGrid_ReplaceStr(sender.id, "XXX", grd);
}
var rowDiv = window.document.getElementById(rowDivName);
//adding new row to table
var newRow = table.insertRow(index);
newRow.id = sender.id + "showRow";
//adding new cell to row
var newTD = document.createElement("TD");
if (table.rows[0].cells[0].colSpan > 1)
newTD.colSpan = table.rows[0].cells[0].colSpan;
else
newTD.colSpan = table.rows[0].cells.length;
var myTD = newRow.appendChild(newTD);
//clone Panel into new cell

var copy = rowDiv;
copy.style.display = "";
myTD.innerHTML = copy.outerHTML;
rowDiv.parentNode.removeChild(rowDiv);
sender.src = HierarGrid_ReplaceStr(sender.src, "plus", "minus");
state = 1;
}
else {
if (existingRow.style.display == "none") {
existingRow.style.display = "";
sender.src = HierarGrid_ReplaceStr(sender.src, "plus", "minus");
state = 1;
}
else {
existingRow.style.display = "none";
sender.src = HierarGrid_ReplaceStr(sender.src, "minus", "plus");
state = 0;
}
}
// ChangeRowState(sender, state);
}
function HierarGrid_ReplaceStr(orgString, findString, replString) {
pos = orgString.lastIndexOf(findString);
return orgString.substr(0, pos) + replString + orgString.substr(pos + findString.length);
}
function GetParentElementByTagName(element, tagName) {
var element = element;
while (element.tagName != tagName)
element = element.parentNode;
return element;
}


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