【C语言】计算1-1/2+1/3-.......+1/99-100的值

<span style="font-size:14px;"><strong style="background-color: rgb(255, 255, 102);">#include <stdio.h>
int main ()
{
int sign = 1;
double deno = 2.0,sum = 1.0,term;
while(deno <= 100)
{
sign = -sign;
term = sign/deno;
sum = sum + term;
deno = deno+1;
}
printf("the sum is %f\n",sum);
return 0;
}</strong></span>

现在我们可以在变量名和操作符上做一些改变,使程序看起来简便一点

<span style="font-size:14px;"><strong style="background-color: rgb(255, 255, 102);">#include <stdio.h>
int main ()
{
int i = 1;
double j;
double sum = 1;
for(j=2; j<=100; j++)
{
i = -i;
sum += i/j;
}
printf("the sum is %f\n",sum);
return 0;
}</strong></span>