An Easy Problem
2015-04-04 21:04
155 查看
题目信息:你有两个整数L和R,你的任务是计算L与R之间数字的平方总和(包括L和R)
#include<stdio.h> int main() { int t; scanf("%d", &t); while (t--) { long long sum = 0, a, b; scanf("%lld%lld", &a, &b); if (a > b) { int t = a; a = b; b = t; } for(long long i = a; i <= b; i++) sum += i * i; printf("%lld\n", sum); } return 0; }分析:做这个题的时候应该注意两个问题(1)输入a与b的前后次序,因为a与b的大小是任意的。(2)定义数据时的类型。
相关文章推荐
- 杭电 ACM 2055 An easy problem
- poj-1152 An Easy Problem!
- hdu 2055 An easy problem (java)
- HDU 2055 An easy problem
- HDU 4729 An Easy Problem for Elfness(树上主席树+LCA+二分)
- HDU 4729 An Easy Problem for Elfness (主席树,树上第K大)
- hdu 2123 An easy problem
- An Easy Problem?!(poj2826线段相交,直线线段相交)
- An easy problem HDU 2132
- POJ 2826 An Easy Problem?!
- hdu 2055 An easy problem (水题)
- POJ 2826 An Easy Problem?!(线段相交,比较角度大小)
- HDU 5475(2015 ICPC上海站网络赛)--- An easy problem(线段树点修改)
- 暑假选拔赛02 ---- an easy problem
- HDOJ 2055 An easy problem
- V-An easy problem
- HDU 2055 An easy problem
- hdu 2601 An easy problem
- HDOJ(HDU) 2132 An easy problem
- JAVA hdu 2132 An easy problem