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HDOJ 2222 Keywords Search

2015-04-04 09:27 274 查看
题意:给出n个模式串和一个主串,求匹配个数

链接:http://acm.hdu.edu.cn/showproblem.php?pid=2222

思路:AC自动机模板题(直接上bin神模板)

注意点:无

以下为AC代码:

Run IDSubmit TimeJudge StatusPro.IDExe.TimeExe.MemoryCode Len.LanguageAuthor
130355052015-03-05 16:56:00Accepted2222920MS31636K3771 BG++luminous11
#include <iostream>
#include <cstdio>
#include <string>
#include <cstring>
#include <iostream>
#include <cstring>
#include <cstdio>
#include <string>
#include <vector>
#include <deque>
#include <list>
#include <map>
#include <set>
#include <queue>
#include <stack>
#include <cmath>
#include <ctime>
#include <cctype>
#include <climits>
#include <iomanip>
#include <cstdlib>
#include <algorithm>
//#include <unordered_map>
//#include <unordered_set>
#define ll long long
#define ull unsigned long long
#define all(x) (x).begin(), (x).end()
#define clr(a, v) memset( a , v , sizeof(a) )
#define pb push_back
#define RDI(a) scanf ( "%d", &a )
#define RDII(a, b) scanf ( "%d%d", &a, &b )
#define RDIII(a, b, c) scanf ( "%d%d%d", &a, &b, &c )
#define RS(s) scanf ( "%s", s )
#define PIL(a) printf ( "%d\n", a )
#define PIIL(a,b) printf ( "%d %d\n", a, b )
#define PIIL(a,b,c) printf ( "%d %d %d\n", a, b, c )
#define PSL(s) printf ( "%s\n", s )
#define REP(i,m,n) for ( int i = m; i <= n; i ++ )
#define DEP(i,m,n) for ( int i = m; i >= n; i -- )
#define REPI(i,m,n,k) for ( int i = m; i <= n; i += k )
#define DEPI(i,m,n,k) for ( int i = m; i >= n; i -= k )
#define READ(f) freopen(f, "r", stdin)
#define WRITE(f) freopen(f, "w", stdout)
using namespace std;
const double pi = acos(-1);
const double eps = 1e-10;
const int dir[4][2] = { 1,0, -1,0, 0,1, 0,-1 };
struct node{
int x, y, cnt;
node(){}
node( int _x, int _y ) : x(_x), y(_y) {}
node( int _x, int _y, int _cnt ) : x(_x), y(_y), cnt(_cnt) {}
};
struct Trie{
int next[500010][30];
int fail[500010];
int end[500010];
int root, L;

int newnode(){
for ( int i = 0; i < 26; i ++ ){
next[L][i] = -1;
}
end[L++] = 0;
return L - 1;
}
void init(){
L = 0;
root = newnode();
}
void insert( char buf[] ){
int len = strlen ( buf );
int now = root;
for ( int i = 0; i < len; i ++ ){
if ( next[now][buf[i]-'a'] == -1 )
next[now][buf[i]-'a'] = newnode();
now = next[now][buf[i]-'a'];
}
end[now] ++;
}
void build(){
queue<int> Q;
fail[root] = root;
for ( int i = 0; i < 26; i ++ ){
if ( next[root][i] == -1 ){
next[root][i] = root;
}
else{
fail[next[root][i]] = root;
Q.push ( next[root][i] );
}
}
while ( ! Q.empty() ){
int now = Q.front();
Q.pop();
for ( int i = 0; i < 26; i ++ ){
if ( next[now][i] == -1 ){
next[now][i] = next[fail[now]][i];
}
else{
fail[next[now][i]] = next[fail[now]][i];
Q.push ( next[now][i] );
}
}
}
}
int query ( char buf[] ){
int len = strlen ( buf );
int now = root;
int res = 0;
for ( int i = 0; i < len; i ++ ){
now = next[now][buf[i]-'a'];
int temp = now;
while ( temp != root ){
res += end[temp];
end[temp] = 0;
temp = fail[temp];
}
}
return res;
}
};
char buf[1000010];
Trie ac;
int main()
{
int T;
int n;
RDI ( T );
while ( T -- ){
RDI ( n );
ac.init();
for ( int i = 0; i < n; i ++ ){
RS ( buf );
ac.insert ( buf );
}
ac.build();
RS ( buf );
PIL ( ac.query(buf) );
}
return 0;
}
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