简易计算器（只有加减乘除和异或运算）

#include <stdio.h>

int add(int x, int y)
{
return x+y;
}
int sub(int x, int y)
{
return x-y;
}
int mul(int x, int y)
{
return x*y;
}
int div(int x, int y)
{
return x/y;
}
int yihuo(int x, int y)
{
return x^y;}

int main()
{
int input = 1;
int x=0;
int y=0;
int ret = 0;
int (*p[6])(int x,int y) = {0,add,sub,mul,div,yihuo};
while(input)
{
printf("********************\n");
printf("**  1:add   2:sub **\n");
printf("**  3:mul   4:div **\n");
printf("   **  5:yihuo  **\n");
printf("********************\n");
scanf("%d",&input);
printf("输入两个操作数:");
scanf("%d %d",&x,&y);
ret = p[input](x,y);
printf("ret = %d\n",ret);
}

return 0;
}