杭电 HDU 1076 An Easy Task

An Easy Task

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)

Total Submission(s): 16217 Accepted Submission(s): 10363



Problem Description
Ignatius was born in a leap year, so he want to know when he could hold his birthday party. Can you tell him?

Given a positive integers Y which indicate the start year, and a positive integer N, your task is to tell the Nth leap year from year Y.

Note: if year Y is a leap year, then the 1st leap year is year Y.



Input
The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.

Each test case contains two positive integers Y and N(1<=N<=10000).



Output
For each test case, you should output the Nth leap year from year Y.



Sample Input

3
2005 25
1855 12
2004 10000

Sample Output

2108
1904
43236

Hint
We call year Y a leap year only if (Y%4==0 && Y%100!=0) or Y%400==0.

Author
Ignatius.L

#include<iostream>
using namespace std;
int main()
{
	int T;
	int Y,N;
	cin>>T;
	while(T--)
	{
		int number=0;int i;
		cin>>Y>>N;
		for( i=Y;;i++)
		{
			if(number==N)
				break;
			else
				if(((i%4==0)&&(i%100!=0))||(i%400==0))
					number++;
		}
		cout<<i-1<<endl;
	}
	return 0;
}