[Leetcode 187, medium] Repeated DNA Sequences
2015-03-27 11:38
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Problem:
All DNA is composed of a series of nucleotides abbreviated as A, C, G, and T, for example: "ACGAATTCCG". When studying DNA, it is sometimes useful to identify repeated sequences within the DNA.
Write a function to find all the 10-letter-long sequences (substrings) that occur more than once in a DNA molecule.
For example,
Analysis:
Solutions:
C++:
Python:
All DNA is composed of a series of nucleotides abbreviated as A, C, G, and T, for example: "ACGAATTCCG". When studying DNA, it is sometimes useful to identify repeated sequences within the DNA.
Write a function to find all the 10-letter-long sequences (substrings) that occur more than once in a DNA molecule.
For example,
Given s = "AAAAACCCCCAAAAACCCCCCAAAAAGGGTTT", Return: ["AAAAACCCCC", "CCCCCAAAAA"].
Analysis:
Solutions:
C++:
vector<string> findRepeatedDnaSequences(string s) { vector<string> r_set_strings; if(s.size() < 10) return r_set_strings; int codebook[26]; codebook['A' - 'A'] = 0; codebook['C' - 'A'] = 1; codebook['G' - 'A'] = 2; codebook['T' - 'A'] = 3; bool hash_substr[1024 * 1024]; memset(hash_substr, false, 1024 * 1024); int size = s.size(); int int_substr = 0; const int mask = (1<<20) - 1; for(int i = 0; i < size; ++i) { int_substr <<= 2; int_substr = (int_substr & mask) | codebook[s[i] - 'A']; if(i < 9) continue; if(!hash_substr[int_substr]) hash_substr[int_substr] = true; else if(find(r_set_strings.begin(), r_set_strings.end(), s.substr(i - 9, 10)) == r_set_strings.end()) r_set_strings.push_back(s.substr(i - 9, 10)); } return r_set_strings; }Java:
Python:
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