leetcode Reverse Integer
2015-03-26 19:48
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int reverse(long long x) { long long m = x; if (x<INT_MIN||x > INT_MAX) { return 0; } if (m < 0) { return 0 - reverse(0 - m); } long long y = 0; while (m > 0) { int c = m % 10; m = m / 10; y = y * 10 + c; } if (y<INT_MIN || y>INT_MAX) { return 0; } return y; }
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