您的位置:首页 > 其它

LeetCode – Refresh – Subsets II

2015-03-24 15:17 211 查看
Nothing fancy. Just skip the duplicated ones as num[i] == num[i-1]

class Solution {
public:
void getComb(vector<vector<int> > &result, vector<int> &num, vector<int> current, int index, int len) {
if (current.size() == len) {
result.push_back(current);
return;
}
for (int i = index; i < num.size(); i++) {
if (i > index && num[i] == num[i-1]) continue;
current.push_back(num[i]);
getComb(result, num, current, i+1, len);
current.pop_back();
}
}
vector<vector<int> > subsetsWithDup(vector<int> &S) {
vector<vector<int> > result;
sort(S.begin(), S.end());
for (int i = 0; i <= S.size(); i++) {
getComb(result, S, vector<int>(), 0, i);
}
return result;
}
};
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: