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python SQLite数据库简单操作

2015-03-17 09:30 267 查看
<span style="font-size:14px;">#!/usr/bin/python

import sqlite3
# create database
conn = sqlite3.connect('test.db') #不存在就创建后再打开
print ("Opened database successfully")

conn.execute('''CREATE TABLE COMPANY
(ID INT PRIMARY KEY     NOT NULL,
NAME           TEXT    NOT NULL,
AGE            INT     NOT NULL,
ADDRESS        CHAR(50),
SALARY         REAL);''')
print ("Table created successfully")

conn.close()

# inset data into database
conn = sqlite3.connect('test.db')
print ("Opened database successfully")

conn.execute("INSERT INTO COMPANY (ID,NAME,AGE,ADDRESS,SALARY) \
VALUES (1, 'Paul', 32, 'California', 20000.00 )");

conn.execute("INSERT INTO COMPANY (ID,NAME,AGE,ADDRESS,SALARY) \
VALUES (2, 'Allen', 25, 'Texas', 15000.00 )");

conn.execute("INSERT INTO COMPANY (ID,NAME,AGE,ADDRESS,SALARY) \
VALUES (3, 'Teddy', 23, 'Norway', 20000.00 )");

conn.execute("INSERT INTO COMPANY (ID,NAME,AGE,ADDRESS,SALARY) \
VALUES (4, 'Mark', 25, 'Rich-Mond ', 65000.00 )");

conn.commit()
print ("Records created successfully")
conn.close()

# select from database

conn = sqlite3.connect('test.db')
print ("Opened database successfully")

cursor = conn.execute("SELECT id, name, address, salary  from COMPANY")
for row in cursor:
print ("ID = %d" % row[0])
print ("NAME = %s" % row[1])
print ("ADDRESS = %s" % row[2])
print ("SALARY = %d" % row[3])
print("\n")

print ("Operation done successfully")
conn.close()

</span>


ref: http://www.w3cschool.cc/sqlite/sqlite-python.html
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