URAL1001解题报告

第一次写blog有点小紧张啊~~~~

1001. Reverse Root

Time limit: 2.0 second

Memory limit: 64 MB

The problem is so easy, that the authors were lazy to write a statement for it!

Input

The input stream contains a set of integer numbers Ai (0 ≤ Ai ≤
1018). The numbers are separated by any number of spaces and line breaks. A size of the input stream does not exceed 256 KB.

Output

For each number Ai from the last one till the first one you should output its square root. Each square root should
be printed in a separate line with at least four digits after decimal point.

Sample

input	output
1427 0 876652098643267843 5276538	2297.0716 936297014.1164 0.0000 37.7757

最重要是读懂题！！！！！！！！！！！！！！！！！！！！！！！！！！！！！！！！！！！！！！；
吃了英语的大亏啊！！；
题意大概是求一堆数的平方根，然后最先输出，输入数中的最后一个数的平方根，从后往前，知道输出 第一个数的平方根；

代码如下；

#include<iostream>
#include<cstdio>
#include<cmath>
using namespace std;
double b[1000001];
int main()
{
double a;
int i=0;
while(~scanf("%lf",&a))
{
b[i]=sqrt(a);
i++;
}
for(int j=i-1;j>=0;j--)
printf("%.4lf\n",b[j]);
return 0;
}