杭电1020-Encoding
2015-03-11 21:26
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[align=left]Problem Description[/align]
Given a string containing only 'A' - 'Z', we could encode it using the following method:
1. Each sub-string containing k same characters should be encoded
to "kX" where "X" is the only character in this sub-string.
2. If the length of the sub-string is 1, '1' should be
ignored.
[align=left]Input[/align]
The first line contains an integer N (1 <= N
<= 100) which indicates the number of test cases.
The next N lines contain N strings. Each string consists of only
'A' - 'Z' and the length is less than 10000.
[align=left]Output[/align]
For each test case, output the encoded string in a
line.
[align=left]Sample Input[/align]
2
ABC
ABBCCC
[align=left]Sample Output[/align]
ABC
A2B3C
#include <cstdlib>
#include <iostream>
#include <string>
using namespace std;
int main(int argc, char *argv[])
{
int n,len,num,i;
cin>>n;
string s;
char temp;
while(n--)
{
cin>>s;
len=s.length();
temp=s[0];
num=1;;
for(i=1;i<len;i++)
{
if(temp==s[i])
num++;
else
{
if(num!=1)
cout<<num<<temp;
else
cout<<temp;
num=1;
temp=s[i];
}
}
if(num!=1)
cout<<num<<temp;
else
cout<<temp;
cout<<endl;
}
system("PAUSE");
return EXIT_SUCCESS;
}
Given a string containing only 'A' - 'Z', we could encode it using the following method:
1. Each sub-string containing k same characters should be encoded
to "kX" where "X" is the only character in this sub-string.
2. If the length of the sub-string is 1, '1' should be
ignored.
[align=left]Input[/align]
The first line contains an integer N (1 <= N
<= 100) which indicates the number of test cases.
The next N lines contain N strings. Each string consists of only
'A' - 'Z' and the length is less than 10000.
[align=left]Output[/align]
For each test case, output the encoded string in a
line.
[align=left]Sample Input[/align]
2
ABC
ABBCCC
[align=left]Sample Output[/align]
ABC
A2B3C
#include <cstdlib>
#include <iostream>
#include <string>
using namespace std;
int main(int argc, char *argv[])
{
int n,len,num,i;
cin>>n;
string s;
char temp;
while(n--)
{
cin>>s;
len=s.length();
temp=s[0];
num=1;;
for(i=1;i<len;i++)
{
if(temp==s[i])
num++;
else
{
if(num!=1)
cout<<num<<temp;
else
cout<<temp;
num=1;
temp=s[i];
}
}
if(num!=1)
cout<<num<<temp;
else
cout<<temp;
cout<<endl;
}
system("PAUSE");
return EXIT_SUCCESS;
}
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