SPOJ problem 42: Adding Reversed Numbers
2015-02-17 15:38
197 查看
这是一道水题，就是让你把给出的两个数倒置后相加再倒回来，模拟一下就行。
#include<cstdio>
int n,m,x,y,t;
int main(){
for(scanf("%d",&t);t;t--){
scanf("%d%d",&n,&m);
x=0;y=0;
for (;n;n/=10)x=x*10+n%10;
for (;m;m/=10)y=y*10+m%10;
x+=y;y=0;
for (;x;x/=10)y=y*10+x%10;
printf("%d\n",y);
}
return 0;
}
内容来自用户分享和网络整理，不保证内容的准确性，如有侵权内容，可联系管理员处理 
相关文章推荐
- SPOJ42 - Adding Reversed Numbers （简单题）
- zoj 2001.Adding Reversed Numbers
- ZOJ 2001 Adding Reversed Numbers
- UVA713 UVALive5539 POJ1504 ZOJ2001 Adding Reversed Numbers
- poj1504 Adding Reversed Numbers
- （高精度） Adding Reversed Numbers (P1504)
- POJ 1504 Adding Reversed Numbers
- POJ 1504 Adding Reversed Numbers…
- (数组的应用二：高精度运算4.2.1)POJ 1504 Adding Reversed Numbers(将一个数取反)
- SPOJ Python Day1: Adding Reversed Numbers
- Problem N-14 Adding Reversed Numbers
- POJ 1504 Adding Reversed Numbers
- poj 1504 Adding Reversed Numbers
- POJ1504-Adding Reversed Numbers（C语言实现）
- poj1504 Adding Reversed Numbers
- zoj_2001 Adding Reversed Numbers
- POJ 1504 Adding Reversed Numbers
- Adding Reversed Numbers(0058)
- ZOJ2001 POJ1504 Adding Reversed Numbers
- zoj2001 Adding Reversed Numbers