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hdu 3966 树链剖分

2015-02-13 20:31 232 查看
不会树链剖分的可以看下面这个链接(本人写的,应该比较简洁易懂)

点击打开链接

就是模板题,没啥好说的,仔细一点一定能过...

本人水逼,wa了好几次...

#include <iostream>
#include <cstdio>
#include <algorithm>
#include <cstring>
#define N 50007

using namespace std;

int head
,cc;

struct Edge
{
    int v,next;
}e[N<<1];

void add ( int u , int v )
{
    e[cc].v = v;
    e[cc].next = head[u];
    head[u] = cc++;
}

int top
,rank
,tid
,dep
,fa
,siz
,son
,a
,tim;

void dfs1 ( int u , int father , int d )
{
    siz[u] = 1 , fa[u] = father , dep[u] = d;
    for ( int i = head[u] ; ~i ; i = e[i].next )
    {
        int v = e[i].v;
        if ( v == father ) continue;
        dfs1 ( v , u , d+1 );
        siz[u] += siz[v];
        if ( son[u] == -1 || siz[son[u]] < siz[v] )
            son[u] = v;
    }
}

void dfs2 ( int u , int tp )
{
    top[u] = tp ; tid[u] = ++tim;
    rank[tid[u]] = u;
    if ( son[u] == -1 ) return;
    dfs2 ( son[u] , tp );
    for ( int i = head[u] ; ~i ; i = e[i].next )
    {
        int v = e[i].v;
        if ( v == fa[u] || v == son[u] ) continue;
        dfs2 ( v , v );
    }
}

struct Node
{
    int l,r,sum,lazy;
}tree[N<<2];

void push_up ( int u )
{
    tree[u].sum = tree[u<<1].sum + tree[u<<1|1].sum ;
}

void push_down ( int u )
{
    int lazy = tree[u].lazy;
    if ( lazy )
    {
        tree[u<<1].sum += lazy*( tree[u<<1].r - tree[u<<1].l + 1 );
        tree[u<<1|1].sum += lazy* ( tree[u<<1|1].r - tree[u<<1|1].l+1);
        tree[u<<1].lazy += lazy;
        tree[u<<1|1].lazy += lazy;
        tree[u].lazy = 0; 
    }   
}

void build ( int u , int left , int right )
{
    tree[u].l = left , tree[u].r = right;
    tree[u].lazy = 0;
    if ( left == right ) 
    {
        tree[u].sum = a[rank[left]];
        return;
    }
    int mid = left + right >> 1;
    build ( u<<1 , left , mid );
    build ( u<<1|1 , mid+1 , right );
    push_up ( u );
}

void update ( int u , int left , int right , int v )
{
    int l = tree[u].l , r = tree[u].r;
    int mid = l + r >> 1;
    if ( left <= l && r <= right )
    {
        tree[u].sum += (r-l+1)*v;
        tree[u].lazy += v;
        return;
    }
    push_down ( u );
    if ( left <= mid && right >= l ) update ( u<<1 , left , right , v );
    if ( left <= r && right > mid ) update ( u<<1|1, left , right , v );
    push_up ( u );
}

int query ( int u , int x )
{
    int l = tree[u].l , r = tree[u].r;
    if ( l == r )
        return tree[u].sum;
    int mid = l + r >> 1;
    push_down ( u );
    int ret = 0;
    if ( x >= l && x <= mid ) ret = query ( u<<1 , x );
    else ret = query ( u<<1|1 , x );
    push_up ( u );
    return ret;
}

int  get ( int x )
{
    return query ( 1 , tid[x] );
}

void change ( int u , int v , int value )
{
    while ( top[u] != top[v] )
    {
        if ( dep[top[u]] < dep[top[v]] ) swap ( u , v );
        update ( 1 , tid[top[u]] , tid[u] , value );
        u = fa[top[u]];
    }
    if ( dep[u] > dep[v] ) swap ( u , v );
    update ( 1 , tid[u] , tid[v] , value );
}

int n,m,p;

void init ( )
{
    cc = 0;
    tim = 0;
    memset ( head , -1 , sizeof ( head ) );
    memset ( son , -1 , sizeof ( son ) );
}

int main ( )
{
    while ( ~scanf ( "%d%d%d" , &n , &m , &p ) )
    {
        for ( int i = 1 ; i <= n ; i++ ) scanf ( "%d" , &a[i] );
        init ( );
        int u , v , b;
        for ( int i = 1 ; i <= m ; i++ )
        {
            scanf ( "%d%d" , &u , &v );
            add ( u , v );
            add ( v , u );
        }
        dfs1 ( 1 , 0 , 0 );
        dfs2 ( 1 , 1 );
        build ( 1 , 1 , n );
        char s[10];
        for ( int i = 1 ; i <= p ; i++ )
        {
            scanf ( "%s" , s );
            if ( s[0] == 'I' ) 
            {
                scanf ( "%d%d%d" , &u , &v , &b );
                change ( u , v , b );
            }
            if ( s[0] == 'D' )
            {
                scanf ( "%d%d%d" , &u , &v , &b );
                change ( u , v , -b );
            }
            if ( s[0] == 'Q' )
            {
                scanf ( "%d" , &b );
                printf ( "%d\n" , get ( b ) );
            }
        }
    }
}
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