poj3070--Fibonacci(矩阵的高速幂)
2015-02-10 10:19
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Fibonacci
Description
In the Fibonacci integer sequence, F0 = 0, F1 = 1, and Fn = Fn −
1 + Fn − 2 for n ≥ 2. For example, the first ten terms of the Fibonacci sequence are:
0, 1, 1, 2, 3, 5, 8, 13, 21, 34, …
An alternative formula for the Fibonacci sequence is
![](http://poj.org/images/3070_1.png)
.
Given an integer n, your goal is to compute the last 4 digits of Fn.
Input
The input test file will contain multiple test cases. Each test case consists of a single line containing n (where 0 ≤ n ≤ 1,000,000,000). The end-of-file is denoted by a single line containing the number −1.
Output
For each test case, print the last four digits of Fn. If the last four digits of Fn are all zeros, print ‘0’; otherwise, omit any leading zeros (i.e., print Fn mod
10000).
Sample Input
Hint
As a reminder, matrix multiplication is associative, and the product of two 2 × 2 matrices is given by
![](http://poj.org/images/3070_2.png)
.
Also, note that raising any 2 × 2 matrix to the 0th power gives the identity matrix:
![](http://poj.org/images/3070_3.gif)
.
Source
Stanford Local 2006
和普通的高速幂的写法同样,不同的是须要计算矩阵相乘,仅仅要写对矩阵的乘法,就没难度了
Time Limit: 1000MS | Memory Limit: 65536K | |
Total Submissions: 9650 | Accepted: 6856 |
In the Fibonacci integer sequence, F0 = 0, F1 = 1, and Fn = Fn −
1 + Fn − 2 for n ≥ 2. For example, the first ten terms of the Fibonacci sequence are:
0, 1, 1, 2, 3, 5, 8, 13, 21, 34, …
An alternative formula for the Fibonacci sequence is
![](http://poj.org/images/3070_1.png)
.
Given an integer n, your goal is to compute the last 4 digits of Fn.
Input
The input test file will contain multiple test cases. Each test case consists of a single line containing n (where 0 ≤ n ≤ 1,000,000,000). The end-of-file is denoted by a single line containing the number −1.
Output
For each test case, print the last four digits of Fn. If the last four digits of Fn are all zeros, print ‘0’; otherwise, omit any leading zeros (i.e., print Fn mod
10000).
Sample Input
0 34 626 6875
Hint
As a reminder, matrix multiplication is associative, and the product of two 2 × 2 matrices is given by
![](http://poj.org/images/3070_2.png)
.
Also, note that raising any 2 × 2 matrix to the 0th power gives the identity matrix:
![](http://poj.org/images/3070_3.gif)
.
Source
Stanford Local 2006
和普通的高速幂的写法同样,不同的是须要计算矩阵相乘,仅仅要写对矩阵的乘法,就没难度了
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