九度 题目1010：A + B

处理好字符串即可。代码：

#include <iostream>
#include <string>
#include <map>

using namespace std;

map<string, int> dict;
string str;
int a, b;

void init()
{
dict["zero"] = 0;
dict["one"] = 1;
dict["two"] = 2;
dict["three"] = 3;
dict["four"] = 4;
dict["five"] = 5;
dict["six"] = 6;
dict["seven"] = 7;
dict["eight"] = 8;
dict["nine"] = 9;
}

int string_to_int(const string& str)
{
int ret = 0;
for (size_t i=0, next=str.find(' ');
next!=string::npos;
i=next+1, next=str.find(' ',i))
{
ret = 10 * ret + dict[str.substr(i, next-i)];
}
return ret;
}

int main()
{
init();
while (getline(cin, str))
{
int plus_index = str.find('+');
int equal_index = str.find('=');
a = string_to_int(str.substr(0, plus_index));
b = string_to_int(str.substr(plus_index+2, equal_index-plus_index-2));
if (a + b != 0)
{
cout << a + b << endl;
} else
{
break;
}
}

return 0;
}