C#+arcengine获得栅格数据的像素值（高程）

此文问获得栅格数据的像元值（即高程），有可能部分见解不到位，望大神看到了不惜指教！

/// <summary>

/// 得到高程（通过像素值）

/// </summary>

/// <param name="maskTifPath">Raster路径</param>

private List<int> GetElevation(string maskTifPath, List<IPoint> pointColList)//pointcollist是点集合，可以参照博文获得点集合

{

IRaster raster = GetRaster(maskTifPath);//参见博文获得raster数据

//得到一段光栅带

IRasterBandCollection rasterBandCollection = (IRasterBandCollection)raster;

for (int icount = 0; icount < rasterBandCollection.Count; icount++)//测试数据count为1

{

IRasterBand rasterBand = rasterBandCollection.Item(icount);

//像素

IRawPixels rawPixels = (IRawPixels)rasterBand;

IRasterProps rasterProps = (IRasterProps)rawPixels;

//IGeoDataset geodataset = (IGeoDataset)raster;

//IEnvelope2 envelop = new EnvelopeClass();

//envelop = (IEnvelope2)geodataset.Extent;

//IPoint point = envelop.UpperLeft;

// 像元大致范围

//double blockX = (double)rasterProps.MeanCellSize().X;//网格X间距

//double blockY = (double)rasterProps.MeanCellSize().Y;//网格Y间距

//double blockArea = blockX * blockY;//网格面积

//int columns = rasterProps.Width;//dem列数

//int rows = rasterProps.Height;//dem行数

// 指定像素块大小

IPnt blockSize = new DblPnt();

//blockSize.X = columns;

//blockSize.Y = rows;

blockSize.X = 5;//赋值为多少比较合适？

blockSize.Y = 5;

//blockSize.X = blockX;

//blockSize.Y = blockY;

//指定像素块大小来创建像素快

IPixelBlock3 pixelBlock = (IPixelBlock3)rawPixels.CreatePixelBlock(blockSize);

IPnt blockOrigin = new DblPnt();

IPoint point = new PointClass();

List<int> pixels = new List<int>();

for (int j = 0; j < pointColList.Count; j++)

{

point = pointColList[j];

blockOrigin.X = point.X;

blockOrigin.Y = point.Y;

// 读取指定位置的像素块（blockOrigin为指定位置）

rawPixels.Read(blockOrigin, (IPixelBlock)pixelBlock);

//存储格网dem的二维数组

System.Array pixelData = (System.Array)pixelBlock.get_PixelDataByRef(icount);

// 获得每一个栅格的高程值

for (int col = 0; col < pixelData.GetLength(0); col++)

{

for (int row = 0; row < pixelData.GetLength(1); row++)

{

pixels.Add(Convert.ToInt32(pixelData.GetValue(col, row)));

}

}

return pixels;

}



}

}

本博文参照http://www.docin.com/p-607056135.html，感谢！