1058. A+B in Hogwarts (20)
2015-02-02 22:24
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题目:
If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enough." Your job is to write a program to
compute A+B where A and B are given in the standard form of "Galleon.Sickle.Knut" (Galleon is an integer in [0, 107], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).
Input Specification:
Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.
Output Specification:
For each test case you should output the sum of A and B in one line, with the same format as the input.
Sample Input:
Sample Output:
注意:
1、哈迷飘过。。。
代码:
If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enough." Your job is to write a program to
compute A+B where A and B are given in the standard form of "Galleon.Sickle.Knut" (Galleon is an integer in [0, 107], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).
Input Specification:
Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.
Output Specification:
For each test case you should output the sum of A and B in one line, with the same format as the input.
Sample Input:
3.2.1 10.16.27
Sample Output:
14.1.28
注意:
1、哈迷飘过。。。
代码:
#include<iostream> using namespace std; int main() { int a[3],b[3]; scanf("%d.%d.%d",&a[0],&a[1],&a[2]); scanf("%d.%d.%d",&b[0],&b[1],&b[2]); a[0]+=b[0]; a[1]+=b[1]; a[2]+=b[2]; if(a[2]>=29) { ++a[1]; a[2] -= 29; } if(a[1]>=17) { ++a[0]; a[1] -= 17; } cout<<a[0]<<'.'<<a[1]<<'.'<<a[2]<<endl; return 0; }
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