27. Remove Element Leetcode Python

Given an array and a value, remove all instances of that value in place and return the new length.

The order of elements can be changed. It doesn't matter what you leave beyond the new length.

1.两个指针 count index

2.当 A[index]!=elem时候就A[count]=A[index]

we need two pointers count and index

when A[index]!=elem A[count]=A[index]

class Solution:
# @param A a list of integers
# @param elem an integer, value need to be removed
# @return an integer
def removeElement(self, A, elem):
count=0
index=0
while index<len(A):
if A[index]!=elem:
A[count]=A[index]
count+=1
index+=1
return count