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HDU 3523 Image copy detection(KM最大匹配)

2015-01-27 09:06 288 查看


HDU 3523 Image copy detection

题目链接

题意:这题事实上题意读懂就简单了,说白了就是1-n放到1-n列,每列的值为每列上数字和该数字的差的绝对值,然后求总和最小

思路:就一KM最大匹配

代码:

#include <cstdio>
#include <cstring>
#include <cmath>
#include <cstdlib>
#include <algorithm>
using namespace std;

const int MAXNODE = 505;

typedef int Type;
const Type INF = 0x3f3f3f3f;

struct KM {
int n, m;
Type g[MAXNODE][MAXNODE];
Type Lx[MAXNODE], Ly[MAXNODE], slack[MAXNODE];
int left[MAXNODE], right[MAXNODE];
bool S[MAXNODE], T[MAXNODE];

void init(int n, int m) {
this->n = n;
this->m = m;
memset(g, 0, sizeof(g));
}

void add_Edge(int u, int v, Type val) {
g[u][v] += val;
}

bool dfs(int i) {
S[i] = true;
for (int j = 0; j < m; j++) {
if (T[j]) continue;
Type tmp = Lx[i] + Ly[j] - g[i][j];
if (!tmp) {
T[j] = true;
if (left[j] == -1 || dfs(left[j])) {
left[j] = i;
right[i] = j;
return true;
}
} else slack[j] = min(slack[j], tmp);
}
return false;
}

void update() {
Type a = INF;
for (int i = 0; i < m; i++)
if (!T[i]) a = min(a, slack[i]);
for (int i = 0; i < n; i++)
if (S[i]) Lx[i] -= a;
for (int i = 0; i < m; i++)
if (T[i]) Ly[i] += a;
}

Type km() {
memset(left, -1, sizeof(left));
memset(right, -1, sizeof(right));
memset(Ly, 0, sizeof(Ly));
for (int i = 0; i < n; i++) {
Lx[i] = -INF;
for (int j = 0; j < m; j++)
Lx[i] = max(Lx[i], g[i][j]);
}
for (int i = 0; i < n; i++) {
for (int j = 0; j < m; j++) slack[j] = INF;
while (1) {
memset(S, false, sizeof(S));
memset(T, false, sizeof(T));
if (dfs(i)) break;
else update();
}
}
Type ans = 0;
for (int i = 0; i < n; i++) {
//if (right[i] == -1) return -1;
//if (g[i][right[i]] == -INF) return -1;
ans += g[i][right[i]];
}
return -ans;
}
} gao;

int t, n, m;

int main() {
int cas = 0;
scanf("%d", &t);
while (t--) {
scanf("%d%d", &n, &m);
gao.init(n, n);
int tmp;
for (int i = 0; i < m; i++) {
for (int j = 0; j < n; j++) {
scanf("%d", &tmp);
for (int k = 0; k < n; k++)
gao.add_Edge(k, j, -abs(tmp - k - 1));
}
}
printf("Case #%d: %d\n", ++cas, gao.km());
}
return 0;
}
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