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std::unary_function

2015-01-09 15:58 183 查看
C++98

Unary function object base class
Note: This class has been deprecated in C++11.

This is a base class for standard unary function objects.

Generically, function objects are instances of a class with member function
operator()
defined. This member function allows the object to be used with the same syntax as a regular function call, and therefore its type can be used as template
parameter when a generic function type is expected.

In the case of unary function objects, this
operator()
member function takes a single parameter.

unary_function is just a base class, from which specific unary function objects are derived. It has no
operator()
member defined (which derived classes are expected to define) - it simply has two public data members that are typedefs of
the template parameters. It is defined as:

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template <class Arg, class Result>
struct unary_function {
typedef Arg argument_type;
typedef Result result_type;
};


Member types

member typedefinitionnotes
argument_typeThe first template parameter (Arg)Type of the argument in member
operator()
result_typeThe second template parameter (Result)Type returned by member
operator()


Example

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// unary_function example
#include <iostream>     // std::cout, std::cin
#include <functional>   // std::unary_function

struct IsOdd : public std::unary_function<int,bool> {
bool operator() (int number) {return (number%2!=0);}
};

int main () {
IsOdd IsOdd_object;
IsOdd::argument_type input;
IsOdd::result_type result;

std::cout << "Please enter a number: ";
std::cin >> input;

result = IsOdd_object (input);

std::cout << "Number " << input << " is " << (result?"odd":"even") << ".\n";

return 0;
}

Edit
& Run

Possible output:

Please enter a number: 2
Number 2 is even.

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