python基础的几个小练习题

题目：

1、写一个程序，判断2008年是否是闰年。

2、写一个程序，用于计算2008年10月1日是这一年的第几天？（2008年1月1日是这一年的第一天）

3、（文件题）有一个“record.txt”的文件，内容如下：

# name, age, score

tom, 12, 86

Lee, 15, 99

Lucy, 11, 58

Joseph, 19, 56

第一栏为姓名(name)，第二栏为年纪(age)，第三栏为得分(score)

现在，写一个Python程序，

1）读取文件

2）打印如下结果：

得分低于60的人都有谁？

谁的名字以L开头？

所有人的总分是多少?

3）姓名的首字母需要大写，该record.txt是否符合此要求？ 如何纠正错误的地方？

4、（练习正则表达式）有一个文件，文件名为output_1981.10.21.txt 。下面使用Python： 读取文件名中的日期时间信息，并找出这一天是周几。将文件改名为output_YYYY-MM-DD-W.txt (YYYY:四位的年，MM：两位的月份，DD：两位的日，W：一位的周几，并假设周一为一周第一天)

以下是程序清单：

#-*-coding:utf-8 -*-

# (1) judge leap year
def judge_leap_year(n):
# if n%4 == 0 and n%100 != 0:
#     return True
# if n%100 == 0 and n%400 == 0:
if (n%4 == 0 and n%100 != 0) or (n%100 == 0 and n%400 == 0):
return True
else:
return False

# ===================================================================
# (2) computing the sum days of any day(**.**.**)
def compute_year_counts(datestr):
# deal with these case:
# 2012.12.2
# 2012/12/2
# 2012-12-2
if datestr.find('.') > 0: date = datestr.split('.')
if datestr.find('/') > 0: date = datestr.split('/')
if datestr.find('-') > 0: date = datestr.split('-')

year = int(date[0])
month = int(date[1])
day = int(date[2])
if (month < 1 or month > 12):
print "the error month!"
return -1
if (day > 31):
print "the error day!"
return -1

days = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]

# nDays = 0
# i = 1
# while i < month:
#     nDays += days[i-1]
#     i = i + 1
nDays = sum(days[i] for i in range(0, month - 1))
if (judge_leap_year(year)):
nDays += 1
return nDays + day

datestring = raw_input("input the datetime info:-->")
print compute_year_counts(datestring)

# ===================================================================
# (3) read and write file: use class if perfect!
class UserProfier(object):
def __init__(self, name, age, score):
self.name = name
self.age = age
self.score = score

def read_file_and_anlysis(filetext):
line_read = []
user_scores = []
has_invalid_name = False #the invalid name

for line in filetext:
if not line.startswith('#') and len(line.strip()) != 0:
if line[0].islower():
line = line[0].upper() + line[1:]
has_invalid_name = True
cur = line.strip().split(', ')
user_scores.append(UserProfier(cur[0], int(cur[1]), int(cur[2])))
line_read.append(line)
# print the file
print "print the file"
for i in line_read:
print i
# statistic the score < 60
print "users whose score lower 60:"
for scores in filter(lambda s: s.score < 60 , user_scores):
print scores.name
# statistic the begin of name which is 'L'
print "users whose name's begin is 'L':"
for names in filter(lambda s: s.name.startswith('L'), user_scores):
print names.name
# statistic the total scores of all one
print "the total scores of everyone:"
allscores = map(lambda s:s.score, user_scores)
print allscores
print reduce(lambda x, y: x+y, allscores, 0)

# open the file
with open("record.txt") as f:
read_file_and_anlysis(f)

# ===================================================================
# (4) the useful example of regular expression
import os, re, datetime

filename = "output_1981.10.21.txt"

date_time = re.search("(?P<year>\d{4})\.(?P<month>\d{2})\.(?P<day>\d{2})\.", filename)

year = date_time.group('year')
month = date_time.group('month')
day = date_time.group('day')

print year, month, day
date = datetime.date(int(year), int(month), int(day))
w = date.weekday() + 1
W = str(w)
os.rename(filename, "output_"+year+'-'+month+'-'+day+'-'+str(w)+".txt")