[Everyday Mathematics]20150114
2015-01-06 16:14
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设 $a_0$, $d$ 给定, $a_k=a_0+kd$, $k=0,1,\cdots,n$. 试求如下 $n+1$ 阶行列式的值: $$\bex \sev{\ba{ccccc} a_0&a_1&a_2&\cdots&a_n\\ a_1&a_0&a_1&\cdots&a_{n-1}\\ a_2&a_1&a_0&\cdots&a_{n-2}\\ \cdots&\cdots&\cdots&\cdots&\cdots\\ a_n&a_{n-1}&a_{n-2}&\cdots&a_0 \ea} \eex$$
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