a letter and a number

a letter and a number

时间限制：3000 ms | 内存限制：65535 KB
难度：1

描述we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;

Give you a letter x and a number y , you should output the result of y+f(x).

输入On the first line, contains a number T(0<T<=10000).then T lines follow, each line is a case.each case contains a letter x and a number y(0<=y<1000).
输出for each case, you should the result of y+f(x) on a line
样例输入

6
R 1
P 2
G 3
r 1
p 2
g 3

样例输出

19
18
10
-17
-14
-4

上传者
苗栋栋

01.

#include<stdio.h>

02.

int

main()

03.

{

04.

int

i,N,k,a[10001]={0},b[10001]={0};

05.

scanf

(

"%d"

,&N);

06.

getchar

();

07.

for

(i=0;i<N;i++)

08.

{

09.

scanf

(

"%c%d"

,&a[i],&b[i]);

10.

getchar

();

11.

}

12.

13.

for

(i=0;i<N;i++)

14.

{

15.

if

(a[i]>=97)

16.

a[i]=96-a[i];

17.

else

18.

a[i]=a[i]-64;

19.

printf

(

"%d\n"

,a[i]+b[i]);

20.

}

21.

return

0;

22.

23.

}