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LEETCODE: Sum Root to Leaf Numbers

2015-01-03 16:15 357 查看
Given a binary tree containing digits from 
0-9
 only, each root-to-leaf path could represent
a number.

An example is the root-to-leaf path 
1->2->3
 which represents the number 
123
.

Find the total sum of all root-to-leaf numbers.

For example,
1
/ \
2   3


The root-to-leaf path 
1->2
 represents the number 
12
.

The root-to-leaf path 
1->3
 represents the number 
13
.

Return the sum = 12 + 13 = 
25
.

/**
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
int sum;
void depthSearch(TreeNode *root, int num) {
if(root->left == NULL && root->right == NULL) sum += num;
if(root->left) depthSearch(root->left, num * 10 + root->left->val);
if(root->right) depthSearch(root->right, num * 10 + root->right->val);
}
int sumNumbers(TreeNode *root) {
if(root == NULL) return 0;
depthSearch(root, root->val);
return sum;
}
};
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