PKU 2084 Game of Connections
2015-01-03 15:12
295 查看
Game of Connections
Description
This is a small but ancient game. You are supposed to write down the numbers 1, 2, 3, . . . , 2n - 1, 2n consecutively in clockwise order on the ground to form a circle, and then, to draw some straight line segments to connect them into number pairs. Every
number must be connected to exactly one another.
And, no two segments are allowed to intersect.
It's still a simple game, isn't it? But after you've written down the 2n numbers, can you tell me in how many different ways can you connect the numbers into pairs? Life is harder, right?
Input
Each line of the input file will be a single positive number n, except the last line, which is a number -1.
You may assume that 1 <= n <= 100.
Output
For each n, print in a single line the number of ways to connect the 2n numbers into pairs.
Sample Input
Sample Output
Time Limit: 1000MS | Memory Limit: 30000K | |
Total Submissions: 7567 | Accepted: 3832 |
This is a small but ancient game. You are supposed to write down the numbers 1, 2, 3, . . . , 2n - 1, 2n consecutively in clockwise order on the ground to form a circle, and then, to draw some straight line segments to connect them into number pairs. Every
number must be connected to exactly one another.
And, no two segments are allowed to intersect.
It's still a simple game, isn't it? But after you've written down the 2n numbers, can you tell me in how many different ways can you connect the numbers into pairs? Life is harder, right?
Input
Each line of the input file will be a single positive number n, except the last line, which is a number -1.
You may assume that 1 <= n <= 100.
Output
For each n, print in a single line the number of ways to connect the 2n numbers into pairs.
Sample Input
2 3 -1
Sample Output
2 5 我滴个乖乖,《算法竞赛入门经典》给的公式是错误的!!!我算了好久 ,但是找到了卡特兰数的模板。高精度不会,还是先学会这种吧。#include <iostream> #include <algorithm> #include <string> #include <cstdio> #include <cstring> using namespace std; int a[105][1050],b[1000]; void catalan() //求卡特兰数 { int i, j, len, carry, temp; a[1][0] = b[1] = 1; len = 1; for(i = 2; i <= 100; i++) { for(j = 0; j < len; j++) //乘法 a[i][j] = a[i-1][j]*(4*(i-1)+2); carry = 0; for(j = 0; j < len; j++) //处理相乘结果 { temp = a[i][j] + carry; a[i][j] = temp % 10; carry = temp / 10; } while(carry) //进位处理 { a[i][len++] = carry % 10; carry /= 10; } carry = 0; for(j = len-1; j >= 0; j--) //除法 { temp = carry*10 + a[i][j]; a[i][j] = temp/(i+1); carry = temp%(i+1); } while(!a[i][len-1]) //高位零处理 len --; b[i] = len; } } int main(void) { memset(a,0,sizeof(a)); catalan(); int n; while(cin>>n&&n!=-1) { // for( j=999;j>=0;j--) if(a [j]) break; for(int i=b -1;i>=0;i--) cout<<a [i]; cout<<endl; // cout<<a <<endl; } return 0; }
相关文章推荐
- pku2084 Game of Connections
- 卡特兰数:poj 2084 Game of Connections+hdu 1023
- POJ 2084 Game of Connections 卡特兰数
- POJ 2084 Game of Connections(卡特兰数,JAVA)
- POJ_2084_Game of Connections
- POJ2084—Game of Connections(c++高精度)
- poj 2084 Game of Connections
- POJ 2084 Game of Connections(JAVA练习)
- poj 2084 Game of Connections
- poj 2084 Game of Connections
- poj2084 Game of Connections
- 20140714 「初等数论 - 卡特兰数」 POJ 2084 Game of Connections
- POJ 2084 Game of Connections
- POJ2084 Game of Connections(catalan数)
- POJ 2084 Game of Connections
- poj 2084 Game of Connections
- poj2084 Game of Connections(Catalan)
- [POJ] 2084 -> Game of Connections
- poj 2084 Game of Connections (卡特兰数,大数乘除)
- poj2084 Game of Connections