您的位置:首页 > 其它

[LeetCode] Clone Graph

2014-12-25 17:00 330 查看
Clone an undirected graph. Each node in the graph contains a
label
and
a list of its
neighbors
.

OJ's undirected graph serialization:
Nodes are labeled uniquely.
We use
#
as a separator for each node, and
,
as
a separator for node label and each neighbor of the node.

As an example, consider the serialized graph
{0,1,2#1,2#2,2}
.
The graph has a total of three nodes, and therefore contains three parts as separated by
#
.

First node is labeled as
0
. Connect node
0
to
both nodes
1
and
2
.
Second node is labeled as
1
. Connect node
1
to
node
2
.
Third node is labeled as
2
. Connect node
2
to
node
2
(itself), thus forming a self-cycle.

Visually, the graph looks like the following:
1
/ \
/   \
0 --- 2
/ \
\_/


/**
* Definition for undirected graph.
* struct UndirectedGraphNode {
*     int label;
*     vector<UndirectedGraphNode *> neighbors;
*     UndirectedGraphNode(int x) : label(x) {};
* };
*/
class Solution {
public:
UndirectedGraphNode *cloneGraph(UndirectedGraphNode *node) {
if(node == NULL) return NULL;
unordered_map<UndirectedGraphNode *,UndirectedGraphNode *> nodeMap;
queue<UndirectedGraphNode *> visit;
visit.push(node);
UndirectedGraphNode * copyNode = new UndirectedGraphNode(node -> label);
nodeMap[node] = copyNode;
while(visit.size() > 0){
UndirectedGraphNode *cur = visit.front();
visit.pop();
for(int i = 0;i < cur -> neighbors.size();i ++){
UndirectedGraphNode *neighbor = cur -> neighbors[i];
if(nodeMap.find(neighbor) == nodeMap.end()){
UndirectedGraphNode *neighborCopy = new UndirectedGraphNode(neighbor -> label);
nodeMap[cur] -> neighbors.push_back(neighborCopy);
nodeMap[neighbor] = neighborCopy;
visit.push(neighbor);
}else{
nodeMap[cur] ->neighbors.push_back(nodeMap[neighbor]);
}
}
}
return copyNode;
}
};
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: