LEETCODE: Length of Last Word

Given a string s consists of upper/lower-case alphabets and empty space characters 

'
'

, return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example, 

Given s = 

"Hello World"

,

return 

5

.
不用解释吧，这题！

class Solution {
public:
int lengthOfLastWord(const char *s) {
int length = strlen(s);
int ii = length - 1;
while(ii >= 0) {
if(*(s + ii) == ' ')
ii --;
else
break;
}

int lastlength = 0;
while(ii >= 0) {
if(*(s + ii) != ' ') {
lastlength ++;
ii --;
}
else
break;
}

return lastlength;
}
};