杭电oj 1001 记录一下

<span style="font-family: Arial, Helvetica, sans-serif; background-color: rgb(255, 255, 255);">今天因为自己不知道在做什么，然后拖到晚上才做的</span>

 1001题目

Problem Description

Hey, welcome to HDOJ(Hangzhou Dianzi University Online Judge).

In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.

 

Input

The input will consist of a series of integers n, one integer per line.

 

Output

For each case, output SUM(n) in one line, followed by a blank line. You may assume the result will be in the range of 32-bit signed integer.

 

Sample Input

1
100

 

Sample Output

1

5050

 

Author

DOOM III

刚开始，英文不好，然后刚开始以为是输入两个数，先输入第一个起始数字，结果提交发现错误啊，我也是醉了，后来搞百度了一下，发现原来这里不是输入两个数，一个数就好了，刚开始应该是没有难度的题，坚持才是胜利

我的代码是这样的

#include<stdio.h>

int main()
{
int a,b,sum = 0,i=1;
while(scanf("%d",&b)!=EOF)
{
for(i =1;i<=b;i++)
sum+=i;
printf("%d\n\n",sum);
sum=0;
}
return 0;
}

    继续坚持，坚持才是胜利。加油