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C++ 算法之 是否为环形链表

2014-12-16 15:32 253 查看
如果有两个头结点指针,一个走的快,一个走的慢,那么若干步以后,快的指针总会超过慢的指针一圈。



bool IsCycleList(ListNode* pHead)
{
	if(pHead== NULL) 
		return false;
	if (pHead->m_pNext == NULL)
	{
		return false;
	}
	ListNode* pFastNode   = pHead;
	ListNode* pSlowNode  = pHead;

	//如果为偶数个,pFastNode->m_pNext->m_pNext为空;如果为奇数个,pFast->m_pNext为空;
	while(pFastNode->m_pNext != NULL && pFastNode->m_pNext->m_pNext != NULL)
	{
		pFastNode = pFastNode->m_pNext->m_pNext;
		pSlowNode = pSlowNode->m_pNext;
		if (pSlowNode == pFastNode)
		{
			break;
		}
	}
	if (pFastNode == NULL || pFastNode->m_pNext == NULL)
	{
		return false;
	}
	else
	{
		return true;
	}
}


完整代码测试:

// CycleList.cpp : 定义控制台应用程序的入口点。
//

#include "stdafx.h"
#include <iostream>
using namespace std;

struct ListNode
{
int m_nValue;
ListNode* m_pNext;
ListNode(int k):m_nValue(k),m_pNext(NULL)
{

}
};

bool IsCycleList(ListNode* pHead) { if(pHead== NULL) return false; if (pHead->m_pNext == NULL) { return false; } ListNode* pFastNode = pHead; ListNode* pSlowNode = pHead; //如果为偶数个,pFastNode->m_pNext->m_pNext为空;如果为奇数个,pFast->m_pNext为空; while(pFastNode->m_pNext != NULL && pFastNode->m_pNext->m_pNext != NULL) { pFastNode = pFastNode->m_pNext->m_pNext; pSlowNode = pSlowNode->m_pNext; if (pSlowNode == pFastNode) { break; } } if (pFastNode == NULL || pFastNode->m_pNext == NULL) { return false; } else { return true; } }
int _tmain(int argc, _TCHAR* argv[])
{

ListNode* head = new ListNode(1);
ListNode* Node1 = new ListNode(2);
ListNode* Node2 = new ListNode(3);
ListNode* Node3 = new ListNode(4);
ListNode* Node4 = new ListNode(5);
ListNode* Node5 = new ListNode(6);
ListNode* Node6 = new ListNode(7);

head->m_pNext = Node1;
Node1->m_pNext = Node2;
Node2->m_pNext = Node3;
Node3->m_pNext = Node4;
Node4->m_pNext = Node5;
Node5->m_pNext = Node6;
Node6->m_pNext = head;

bool b = IsCycleList(head);
cout<<b<<endl;

getchar();

return 0;
}

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